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Home » \( 9^4 = (81)^2 \equiv (81 \mod 17 = 13)^2 = 169 \equiv 16 - Groen Casting

\( 9^4 = (81)^2 \equiv (81 \mod 17 = 13)^2 = 169 \equiv 16 - Groen Casting

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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But use identity:
z =
ho \cos\phi = c \sin\phi \cos\phi = rac{c}{2} \sin(2\phi)
Alternatively, use:
ho = c \sin\phi \Rightarrow
ho^2 = c^2 \sin^2\phi
But \(
ho^2 = x^2 + y^2 + z^2\), and \(\sin^2\phi = 1 - \cos^2\phi = 1 - rac...
ho^2}\)
x^2 + y^2 = c^2 \sin^4\phi, \quad z = c \sin\phi \cos\phi

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