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Home » B∩D : 26+15 = 41 → 41^12 - Groen Casting

B∩D : 26+15 = 41 → 41^12 - Groen Casting

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 Check each solution in the original equation:

📌 \( \theta = 30^\circ \): \( \cos 60^\circ = \frac{1}{2},\ \sin 30^\circ = \frac{1}{2} \) → valid

📌 \( \theta = 150^\circ \): \( \cos 300^\circ = \frac{1}{2},\ \sin 150^\circ = \frac{1}{2} \) → valid

📌 \( \theta = 270^\circ \): \( \cos 540^\circ = \cos 180^\circ = -1,\ \sin 270^\circ = -1 \) → valid

📌 All are valid.

📌 \boxed{30^\circ,\ 150^\circ,\ 270^\circ}

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-5n + 14.40 = 7.80
-5n = 7.80 - 14.40 = -6.60
n = \frac{6.60}{5} = 1.32
Setze \( n = 1.32 \) zurück in \( p = 3.60 - 2n \):
p = 3.60 - 2(1.32) = 3.60 - 2.64 = 0.96
Somit kosten die Stifte \$0,96, was 96 Cent entspricht.
Frage: Was ist der größte ganzzahlige Wert von \( x \), der \( 3x + 7...
Lösung: Löse die Ungleichung:
3x + 7 < 16
Subtrahiere 7 von beiden Seiten:

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