But \(d\) must be an integer. So \(m + n\) must divide 2025 evenly, and be at least 2. We seek the largest divisor \(d\) of 2025 such that \( \frac2025d \geq 2 $ and $m + n = \frac2025d$ is minimized among valid coprime pairs. The smallest possible $m + n \geq 2$ is 3 (e.g., $m = 1, n = 2$), which is coprime. Then: - Groen Casting