However, correct interpretation: if parts arrive every 1.25 s and take 8.5 s to process, then at any time, number of active parts = \( \frac8.51.25 = 6.8 \), but in steady state with continuous flow, the number in process is \( \textarrival rate \times \textservice time = \frac11.25 \times 8.5 = 6.8 \). Since partial parts aren’t physical, but for modeling, we report as computed. - Groen Casting