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Home » n - 2 = \frac1620180 = 9 - Groen Casting

n - 2 = \frac1620180 = 9 - Groen Casting

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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🔥 Popular Posts

An epidemiologist analyzing cumulative case data finds a pattern where...
We seek the smallest positive integer \( n \) such that:
n^3 \equiv 1 \pmod{1000}.
We solve \( n^3 \equiv 1 \pmod{8} \) and \( n^3 \equiv 1 \pmod{125} \)...
Step 1: Solve \( n^3 \equiv 1 \pmod{8} \)
Try \( n = 1 \): \( 1^3 = 1 \equiv 1 \mod 8 \)
\( n = 3 \): \( 27 \equiv 3 \mod 8 \)
\( n = 5 \): \( 125 \equiv 5 \mod 8 \)
\( n = 7 \): \( 343 \equiv 7 \mod 8 \)
\( n = 1 \) works.

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