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Home » Now compute $ \mathbfa \times \mathbfb $: - Groen Casting

Now compute $ \mathbfa \times \mathbfb $: - Groen Casting

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Multiply both sides by the denominator:
500(1 + 9e^{-0.5t}) = 1000
Divide both sides by 500:
+ 9e^{-0.5t} = 2
9e^{-0.5t} = 1
e^{-0.5t} = \frac{1}{9}
-0.5t = \ln\left(\frac{1}{9}\right) = -\ln 9
Solve for \(t\):
t = \frac{-\ln 9}{-0.5} = \frac{\ln 9}{0.5} = 2 \ln 9 = \ln(9^2) = \ln...
Alternatively, express the final result clearly:

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