Solution: As $ x o \infty $, $ e^-0.5x o 0 $, so $ P(x) o rac1001 + 0 = 100 $. As $ x o -\infty $, $ e^-0.5x o \infty $, so $ P(x) o 0 $. The range is $ (0, 100) $. oxed(0, 100) - Groen Casting
Mar 01, 2026
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