Solution: Set $ 20 + 80e^-0.1t = 40 $. Subtract 20: $ 80e^-0.1t = 20 $. Divide by 80: $ e^-0.1t = 0.25 $. Take natural logarithm: $ -0.1t = \ln(0.25) $. Solve: $ t = -\frac\ln(0.25)0.1 = \frac\ln(4)0.1 \approx \frac1.3860.1 = 13.86 $. Round to two decimal places: $ \boxed13.86 $ minutes.The Analytical Engine, designed by Charles Babbage, is considered a precursor to modern computers. If Babbage’s design allows a program to execute 120 distinct operations and each operation requires 3 memory accesses, how many total memory accesses are needed to complete the program once? - Groen Casting