Solution: To solve for $\mathbfv$, we use the cross product equation $\mathbfv \times \mathbfw = \mathbfp$. Let $\mathbfv = \beginpmatrix v_1 \\ v_2 \\ v_3 \endpmatrix$. The cross product $\mathbfv \times \mathbfw$ is calculated as $\beginpmatrix v_2 \cdot 3 - v_3 \cdot (-1) \\ v_3 \cdot 2 - v_1 \cdot 3 \\ v_1 \cdot (-1) - v_2 \cdot 2 \endpmatrix = \beginpmatrix 3v_2 + v_3 \\ 2v_3 - 3v_1 \\ -v_1 - 2v_2 \endpmatrix$. Setting this equal to $\mathbfp = \beginpmatrix 5 \\ 0 \\ -2 \endpmatrix$, we get the system: - Groen Casting
Mar 01, 2026
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