\tan \theta = \frac\sqrt1 - \left(\frac13\right)^2\frac13 = \frac\sqrt1 - \frac19\frac13 = \frac\sqrt\frac89\frac13 = \frac\frac2\sqrt23\frac13 = 2\sqrt2 - Groen Casting
Mar 01, 2026
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