Thus, \(d\) must be a divisor of 2024, and \(m + n = \frac2024d\). To maximize \(d\), we minimize \(m + n\), which is minimized when \(m + n = 2\), since \(m, n \geq 1\) and coprime. The only such pair is \(m = 1\), \(n = 1\), which are coprime. Then: - Groen Casting
Mar 01, 2026
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